Question
In an isosceles triangle ΔABC, AB = AC and ∠A = 80°. The bisector of ∠B and ∠C meet at D. The ∠BDC is equal to.
Answer: Option C
∵ AB = AC
Point D is the incenter
∴ ∠BDC = 90° + $$\frac{1}{2}$$ ∠A
= 90° + $$\frac{1}{2}$$ × 80°
= 90° + 40°
= 130°
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∵ AB = AC
Point D is the incenter
∴ ∠BDC = 90° + $$\frac{1}{2}$$ ∠A
= 90° + $$\frac{1}{2}$$ × 80°
= 90° + 40°
= 130°
Was this answer helpful ?
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