In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF, when Options: A . &nbsp∠BAC = ∠EFD B . &nbsp∠ACB = ∠EDF C . &nbsp∠ABC = 2∠DEF D . &nbsp∠ABC = ∠DEF

In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF

Question

In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF, when

Options:

A . ∠BAC = ∠EFD

B . ∠ACB = ∠EDF

C . ∠ABC = 2∠DEF

D . ∠ABC = ∠DEF

Answer: Option D

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