Question
If π∑i=1i =
n(n+1)2, then π∑i=1(3i−2) =
n(n+1)2, then π∑i=1(3i−2) =
Answer: Option A
:
A
π∑i=1 = 3π∑i=1i - 2π∑i=11 = 3
n(n+1)2 - 2n =
n(3n−1)2
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:
A
π∑i=1 = 3π∑i=1i - 2π∑i=11 = 3
n(n+1)2 - 2n =
n(3n−1)2
Was this answer helpful ?
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