Question
If α is a repeated root of ax2+bx+c=0 then limx→αsin(ax2+bx+c)(x−α)2 is
Answer: Option B
:
B
limx→αsin(ax2+bx+c)(x−α)2=limx→αsina(x−α)(x−α)(x−α)2
=limx→αsina(x−α)2a(x−α)2×a=a
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:
B
limx→αsin(ax2+bx+c)(x−α)2=limx→αsina(x−α)(x−α)(x−α)2
=limx→αsina(x−α)2a(x−α)2×a=a
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