Question
The value oflimx→03√1+sinx−3√1−sinxxis
Answer: Option A
:
A
limx→03√1+sinx−3√1−sinxx=limx→0(1+sinx)−(1−sins)(1+sinx)2/3+(1+sinx)2/3+(1−sinx)2/3(1−sinx)2/3×1x=limx→02(1+sinx)2/3+(1+sinx)1/3+(1−sinx)1/3+(1−sinx)2/3×sin(x)x
= 23.1=23
Was this answer helpful ?
:
A
limx→03√1+sinx−3√1−sinxx=limx→0(1+sinx)−(1−sins)(1+sinx)2/3+(1+sinx)2/3+(1−sinx)2/3(1−sinx)2/3×1x=limx→02(1+sinx)2/3+(1+sinx)1/3+(1−sinx)1/3+(1−sinx)2/3×sin(x)x
= 23.1=23
Was this answer helpful ?
Latest Videos
Latest Test Papers
Submit Solution