Question
If x+x−1=11, evaluate x2+x−2.
Answer: Option A
:
A
x+x−1=11
(x+x−1)2=112 [Squaring both the sides]
⇒(x)2+(x−1)2+2(x)(x−1)=121
⇒x2+x−2+2=121 [∵(x)(x−1)=x0=1]
⇒x2+x−2=121−2=119
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:
A
x+x−1=11
(x+x−1)2=112 [Squaring both the sides]
⇒(x)2+(x−1)2+2(x)(x−1)=121
⇒x2+x−2+2=121 [∵(x)(x−1)=x0=1]
⇒x2+x−2=121−2=119
Was this answer helpful ?
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