If $$x\left( {3 - \frac{2}{x}} \right) = \frac{3}{x}{\text{,}}$$ then the value of $${x^2}{\text{ + }}\frac{1}{{{x^2}}}$$ is? Options: A . &nbsp$${\text{2}}\frac{1}{9}$$ B . &nbsp$${\text{2}}\frac{4}{9}$$ C . &nbsp$${\text{3}}\frac{1}{9}$$ D . &nbsp$${\text{3}}\frac{4}{9}$$

If $$x\left( {3 - \frac{2}{x}} \right) = \frac{3}{x}{\text{,}}$$ then the v

Question

If $$x\left( {3 - \frac{2}{x}} \right) = \frac{3}{x}{\text{,}}$$ then the value of $${x^2}{\text{ + }}\frac{1}{{{x^2}}}$$ is?

Options:

A . $${\text{2}}\frac{1}{9}$$

B . $${\text{2}}\frac{4}{9}$$

C . $${\text{3}}\frac{1}{9}$$

D . $${\text{3}}\frac{4}{9}$$

Answer: Option B

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