Sail E0 Webinar
Question

If x is a whole number, then x2 ( x2 - 1) is always divisible by :

Options:
A .  12
B .  24
C .  12 - x
D .  Multiple of 12
E .  None of these
Answer: Option A

 -  Putting = 2, we get 22 (22 - 1) = 12. So, x2(x2 - 1) is always divisible by 12.


The given expression is x2 (x2 - 1). Since x is a whole number, we can assume it to be a positive integer.

We can factorise the expression in the following way:

x2 (x2 - 1) = (x2 - 1) (x2 + 1)

Now, we can use the identity (a - b) (a + b) = a2 - b2

Substituting a = x2 and b = 1 in the identity, we get

x2 (x2 - 1) = x2 - 1

Now, we can use the divisibility rule for 12 which states that a number is divisible by 12 if it is divisible by both 3 and 4.

Since x2 is a multiple of 4 (4 divides x2) and 1 is a multiple of 3 (3 divides 1), we can conclude that the expression x2 (x2 - 1) is divisible by 12.

Hence, the correct answer is Option A. 12.

Definitions and Formulas
Divisibility Rule for 12 : A number is divisible by 12 if it is divisible by both 3 and 4.
Identity : (a - b) (a + b) = a2 - b2

If you think the solution is wrong then please provide your own solution below in the comments section .


Was this answer helpful ?
Next Question

1 Comments

12

Submit Solution

Your email address will not be published. Required fields are marked *

Latest Videos

Latest Test Papers