Question
If the first term of an A.P. is a and nth term is b, then its common difference is
Answer: Option B
In the given A.P.
First term = a and nth term = b
$$\eqalign{
& \therefore a + \left( {n - 1} \right)d = b \cr
& \Rightarrow \left( {n - 1} \right)d = b - a \cr
& \Rightarrow d = \frac{{b - a}}{{n - 1}} \cr} $$
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In the given A.P.
First term = a and nth term = b
$$\eqalign{
& \therefore a + \left( {n - 1} \right)d = b \cr
& \Rightarrow \left( {n - 1} \right)d = b - a \cr
& \Rightarrow d = \frac{{b - a}}{{n - 1}} \cr} $$
Was this answer helpful ?
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