If $$\sqrt {x + \frac{x}{y}} = x\sqrt {\frac{x}{y}} {\text{,}}$$ where x and y are positive real numbers, then y is equal to ? Options: A . &nbsp$${\text{x}} + 1$$ B . &nbsp$${\text{x}} - 1$$ C . &nbsp$${{\text{x}}^2} + 1$$ D . &nbsp$${{\text{x}}^2} - 1$$

If $$\sqrt {x + \frac{x}{y}} = x\sqrt {\frac{x}{y}} {\text{,}}$$ where x a

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