If parallelogram ABCD and rectangle ABEM are of equal area, then: Options: A . &nbspPerimeter of AMEB = Perimeter of ADCB B . &nbspPerimeter of AMEB C . &nbspPerimeter of AMEB >Perimeter of ADCB D . &nbspPerimeter of AMEB = 12 Perimeter of ADCB

If parallelogram ABCD and rectangle ABEM are of equal area, then:

Question

If parallelogram ABCD and rectangle ABEM are of equal area, then:

Options:

A . Perimeter of AMEB = Perimeter of ADCB

B . Perimeter of AMEB

C . Perimeter of AMEB >Perimeter of ADCB

D . Perimeter of AMEB = 12 Perimeter of ADCB

Answer: Option B
:
B

In right angled

Δ A M D

A D^{2}

A M^{2}

M D^{2}

(by Pythagoras theorem)

\Rightarrow A D > A M

Similarly,In right angled

Δ B E C

B C^{2}

B E^{2}

E C^{2}

\Rightarrow B C > B E

AB = DC = ME (opposite sides of rectangle and parallelogram)
Perimeter of rectangle = AM + ME + EB + AB.
Perimeter of parallelogram = AB + BC + DC + AD.
Hence Perimeter of ADCB

>

Perimeter of AMEB.

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