If $$\log 3\log \left( {{3^x} - 2} \right)\,$$ and $$\log \left( {{3^x} + 4}

Question

If $$\log 3\log \left( {{3^x} - 2} \right)\,$$ and $$\log \left( {{3^x} + 4} \right)$$ are in arithmetic progression, then x is equal to

Options:

A . $$\frac{8}{3}$$

B . $$\log {3^8}$$

C . $$\log {2^3}$$

D . 8

Answer: Option C

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