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Question
If $${\left( {r\cos \theta - \sqrt 3 } \right)^2}$$    + $${\left( {r\sin \theta - 1} \right)^2}$$   = 0, then the value of $$\frac{{r\tan \theta + \sec \theta }}{{r\sec \theta + \tan \theta }}$$   is equal to?
Options:
A .  $$\frac{4}{5}$$
B .  $$\frac{3}{5}$$
C .  $$\frac{{\sqrt 3 }}{4}$$
D .  $$\frac{{\sqrt 5 }}{4}$$
Answer: Option A

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