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If in a triangle ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $$\frac{{AD}}{{BD}}$$ = $$\frac{3}{5}$$. If AC = 4 cm, then AE is
Options:
A .  1.5 cm
B .  2.0 cm
C .  1.8 cm
D .  2.4 cm
Answer: Option A

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