Question
If in a triangle ABC, BE and CF are two medians perpendicular to each other and if AB = 19 cm and AC = 22 cm then the length of BC is :
Answer: Option D
Given :
AB = 19 cm, AC = 22 cm
∵ BE ⊥ CF (given), [Medians CF & BE are perpendicular to each other]
⇒ In this case
⇒ We know,
  AB2 + AC2 = 5(BC)2
⇒ 192 + 222 = 5(BC)2
⇒ 361 + 484 = 5(BC)2
⇒ 845 = 5(BC)2
⇒ (BC)2 = 169
⇒ BC = 13 cm
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Given :
AB = 19 cm, AC = 22 cm
∵ BE ⊥ CF (given), [Medians CF & BE are perpendicular to each other]
⇒ In this case
⇒ We know,
  AB2 + AC2 = 5(BC)2
⇒ 192 + 222 = 5(BC)2
⇒ 361 + 484 = 5(BC)2
⇒ 845 = 5(BC)2
⇒ (BC)2 = 169
⇒ BC = 13 cm
Was this answer helpful ?
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