If $$\frac{{5 + 9 + 13 + ...\,{\text{to}}\,n\,{\text{terms}}}}{{7 + 9 + 11 + ...

Question

If $$\frac{{5 + 9 + 13 + ...\,{\text{to}}\,n\,{\text{terms}}}}{{7 + 9 + 11 + ...\,{\text{to}}\,\left( {n + 1} \right)\,{\text{terms}}}}$$ $$ = \frac{{17}}{{16}},$$ then n = ?

Options:

A . 8

B . 7

C . 10

D . 11

Answer: Option B

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