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Question
If f"(x) > 0  x ϵ R then for any two real numbers x1 and x2 , (x1  x2)
Options:
A .  f(x1 + x22) > f(x1) + f(x2)2
B .  f(x1 + x22) 
C .  f′(x1 + x22) > f′(x1) + f′(x2)2
D .  f′(x1 + x22) 
Answer: Option B
:
B
Let A = (x1,f(x1)) and B = (x2,f(x2)) be any two points on the graph of y = f(x).
Since f"(x) > 0, in the graph of the function tangent will always lie below the curve. Hence chord AB will lie completely above the graph of y = f(x).
Hence f(x1)+f(x2)2>f(x1+x22)

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