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Question
If DIAMOND is coded as VQYMKLV, how can FEMALE be coded?
Options:
A .  TUMYNU
B .  UVNZOV
C .  UVNYNV
D .  TVNYNV
E .  TUMZOU
Answer: Option A

 -  If in the word, a letter is nth letter from the beginning of the English alphabets, then in the code the corresponding letter is the (n+1) th letter from the end of the alphabets

The given code DIAMOND is coded as VQYMKLV. To solve this coding problem, we need to understand the pattern used to convert the given word into its coded form.

Solution:

Let's analyze the given code for the word DIAMOND:

D I A M O N D

V Q Y M K L V

We can see that each letter of the original word is replaced by a corresponding letter in the coded word. The replacement pattern used here is as follows:

  • The first letter of the original word is replaced by the 22nd letter of the alphabet (V)
  • The second letter of the original word is replaced by the 17th letter of the alphabet (Q)
  • The third letter of the original word is replaced by the 25th letter of the alphabet (Y)
  • The fourth letter of the original word is replaced by the 13th letter of the alphabet (M)
  • The fifth letter of the original word is replaced by the 11th letter of the alphabet (K)
  • The sixth letter of the original word is replaced by the 12th letter of the alphabet (L)
  • The seventh letter of the original word is replaced by the 22nd letter of the alphabet (V)

Using the same pattern, we can now encode the word FEMALE:

F E M A L E

T U M Y N U

Therefore, the coded form of FEMALE is TUMYNU. Hence, the answer is option A.

To summarize, in this problem, we need to understand the pattern used to convert the given word into its coded form. In general, such problems can be solved by identifying the replacement pattern used and applying it to the new word. In this case, we saw that each letter of the original word is replaced by a corresponding letter in the coded word according to their alphabetical position.


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