Question
If ax = by, then:
Answer: Option C
$$\eqalign{
& {a^x} = {b^y} \cr
& \Rightarrow \log {a^x} = \log {b^y} \cr
& \Rightarrow x\log a = y\log b \cr
& \Rightarrow {{\log a} \over {\log b}} = {y \over x} \cr} $$
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$$\eqalign{
& {a^x} = {b^y} \cr
& \Rightarrow \log {a^x} = \log {b^y} \cr
& \Rightarrow x\log a = y\log b \cr
& \Rightarrow {{\log a} \over {\log b}} = {y \over x} \cr} $$
Was this answer helpful ?
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