If ∠ACD=90∘ and CF is the angular bisector of ∠ACD, then ∠BCF= __∘.

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If $∠ A C D = 90^{\circ}$ and $C F$ is the angular bisector of $∠ A C D$ , then $∠ B C F =$ __ $^{\circ}$ .

Options:

Answer: Option A
:
Given,

∠ A C D

=

90^{\circ}

and

C F

is the angular bisector of

∠ A C D

, so

∠ D C F = 45^{\circ}

. So,

B C F = 135^{\circ}

.

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