Question
If a=2√2i then which of the following is correct?
Answer: Option A
:
A
We have a =√2i=√2(cosπ2+isinπ2)12=√2(eiπ2)12=√2eiπ4=√2(1√2+i√2i)=1+i
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A
We have a =√2i=√2(cosπ2+isinπ2)12=√2(eiπ2)12=√2eiπ4=√2(1√2+i√2i)=1+i
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