Question
If A=(1,3,-5) and B=(3,5,-3), then the vector equation of the plane passing through the midpoint of AB and perpendicular to AB is
Answer: Option A
:
A
−−→AB=−−→OB−−−→OA=(3^i+5^j−3^k)−(^i+3^j−5^k)=2^i+2^j+2^k
Midpoint of AB is (2, 4, -4)
Vector equation of the plane is [r−(2^i+4^j−4^k)].(2^i+2^j+2^k)=0
⇒r.(^i+^j+^k)=2+4−4⇒r.(^i+^j+^k)=2
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:
A
−−→AB=−−→OB−−−→OA=(3^i+5^j−3^k)−(^i+3^j−5^k)=2^i+2^j+2^k
Midpoint of AB is (2, 4, -4)
Vector equation of the plane is [r−(2^i+4^j−4^k)].(2^i+2^j+2^k)=0
⇒r.(^i+^j+^k)=2+4−4⇒r.(^i+^j+^k)=2
Was this answer helpful ?
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