Question
If 5f(x) + 3f (1x) = x + 2 and y = x f(x), then (dydx)x=1 is equal to
Answer: Option B
:
B
5f(x)+3f(1x)=x+2........(i)
Replacingxby1x
∴5f(1x)+3f(x)=1x+2...(ii)
FromEq.(i).
25f(x)+15f(1x)=5x+10....(iii)
andfromEq.(ii)
9f(x)+15f(1x)=3x+6.....(iv)
SubtractingEq.(iv)from(iii),weget
∴16f(x)=5x−3x+4
∴xf(x)=5x2−3+4x16=y
∴dydx=10x+416
∴dydx|x=1=10+416
=78
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:
B
5f(x)+3f(1x)=x+2........(i)
Replacingxby1x
∴5f(1x)+3f(x)=1x+2...(ii)
FromEq.(i).
25f(x)+15f(1x)=5x+10....(iii)
andfromEq.(ii)
9f(x)+15f(1x)=3x+6.....(iv)
SubtractingEq.(iv)from(iii),weget
∴16f(x)=5x−3x+4
∴xf(x)=5x2−3+4x16=y
∴dydx=10x+416
∴dydx|x=1=10+416
=78
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