Question
If `2^x = 4^y = 8^z and ((1)/(2x) + (1)/(4y) + (1)/(6z)) = 24/7`, then the value of z is:
Answer: Option C
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`2^x = 4^y = 8^z hArr 2^x = 2^(2y) = 2^(3z) hArr x = 2y = 3z`
`:. (1)/(2x) + (1)/(4y) + (1)/(6z) = 24/7 hArr (1)/(6z) + (1)/(6z) + (1)/(6z) = 24/7`
`hArr (3)/(6z) = 24/7 hArr z = (3/6 xx 7/24) = 7/48`
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