Question
Given that P(3,2,-4), Q(5,4,-6) and R(9,8,-10) are collinear, find the ratio in which Q divides PR.
Answer: Option A
:
A
Let Qdivide PR in the ratio k:1. Equate the x-coordinateof the point of division to 5.
∴3+9kk+1=53+9k=5k+54k=2k=12
Since it is given that P, Q and Rare collinear, we need to calculate k onlyfor any one of thecoordinates.
Was this answer helpful ?
:
A
Let Qdivide PR in the ratio k:1. Equate the x-coordinateof the point of division to 5.
∴3+9kk+1=53+9k=5k+54k=2k=12
Since it is given that P, Q and Rare collinear, we need to calculate k onlyfor any one of thecoordinates.
Was this answer helpful ?
More Questions on This Topic :
Question 2. The point (2,0,3) lies in which octant?....
Question 4. The point (1,5,-6) lies in which octant?....
Latest Videos
Latest Test Papers
Submit Solution