Question
Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to:
Answer: Option C
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xz = y2 \(\Leftrightarrow \) 10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40
z = \(\frac{140}{48}\) = \(\frac{35}{12}\) = 2.9 (approx.)
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