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Question

Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to:

Options:
A .  1.45
B .  1.88
C .  2.9
D .  3.7
Answer: Option C

xz = y2     \(\Leftrightarrow \)   10(0.48z) = 10(2 x 0.70) = 101.40


 0.48z = 1.40


 z = \(\frac{140}{48}\)\(\frac{35}{12}\) =  2.9 (approx.)


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