Question
Given, f(x) = log1+x1−x and g(x) =3x+x31+3x2 then (fog) (x) equals
Answer: Option B
:
B
(fog)(x)=f(g(x))=f(3x+x31+3x2)=log1+3x2+3x+x31+3x2−3x−x3=log(1+x)3(1−x)3=3f(x)
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B
(fog)(x)=f(g(x))=f(3x+x31+3x2)=log1+3x2+3x+x31+3x2−3x−x3=log(1+x)3(1−x)3=3f(x)
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