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Answer: Option A
:
A and D
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A and D
ΔAOB is an isosceles triangle (OA = OB; Radii),
⇒∠OAB=∠OBA=50∘.
In ΔAOB,
∠OAB+∠OBA+∠AOB=180∘
Hence, ∠AOB=80∘
The angle subtended by an arc of the circle at its centre is double the angle subtended by it at any point on the remaining part of the circle.
Therefore, ∠ACB=12∠AOB=40∘.
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