Fundamental momentum equation for a hydraulic jump, is Options: A . &nbspD₁² - D₂² = (2q/g) × (V₁ - V₂) B . &nbspD₂² - D₁² = (2q/g) × (V - V₂) C . &nbspD₁² - D₂² = (2q/g) × (V₂ - V₁) D . &nbspD₁² + D₂² = (2q/g) × (V₂ - V₁)

Fundamental momentum equation for a hydraulic jump, is

Question

Fundamental momentum equation for a hydraulic jump, is

Options:

A . D₁² - D₂² = (2q/g) × (V₁ - V₂)

B . D₂² - D₁² = (2q/g) × (V - V₂)

C . D₁² - D₂² = (2q/g) × (V₂ - V₁)

D . D₁² + D₂² = (2q/g) × (V₂ - V₁)

Answer: Option B

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