Question
Four spheres, each of mass 'M' and radius 'r' are situated at the four corners of square of side 'R'. The moment of inertia of the system about an axis perpendicular to the plane of square and passing through its centre will be
Answer: Option B
:
B
M. I. of sphere A about its diameter IO′=25Mr2
Now M.I. of sphere A about an axis perpendicular to the plane of square and passing through its centre will be
IO=IO′+M(R√2)2=25Mr2+MR22
Moment of inertia of system (i.e. four sphere) =4IO=4[25Mr2+MR22]=25M[4r2+5R2]
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B
M. I. of sphere A about its diameter IO′=25Mr2
Now M.I. of sphere A about an axis perpendicular to the plane of square and passing through its centre will be
IO=IO′+M(R√2)2=25Mr2+MR22
Moment of inertia of system (i.e. four sphere) =4IO=4[25Mr2+MR22]=25M[4r2+5R2]
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