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Question
For unrooted trees, the number of unrooted tree topologies (NU) is ________
Options:
A .  NU = (2n− 5)!/2ⁿ⁻³(n− 5)!
B .  NU = (2n− 5)!/2ⁿ⁻³(n− 3)!
C .  NU = (2n− 5)!/2¯²(n− 3)!
D .  NU = (2n− 5)!/2ⁿ(n− 3)!
Answer: Option B
Answer: (b).NU = (2n− 5)!/2ⁿ⁻³(n− 3)!

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