For constructing a right angle without a protractor, which of the following method/s is/are used? Options: A . &nbsp Angle Bisector B . &nbsp 60 ∘ angle construction C . &nbsp Median D . &nbsp Construction of triangle

Answer: Option A : A and B To construct a right angle triangle, the following steps should be followed: 1. Draw a line OB of given length. 2. With O as centre, make an arc of any radius intersecting OB at X. 3. With X as a centre, draw another arc keeping the radius same intersecting the previous arc at D. 4. ∠ DOB will be 60 ∘ . 5. With D as a centre and keeping the radius same, draw another arc intersecting the first arc at C. 6. ∠ COB will be 120 ∘ . 7. Bisect COD drawing two equal arcs from each points intersecting at E. 8. Join EO and extend till A. ∠ AOB will be 90 ∘ . So, it can be seen that both 60 ∘ and angle bisector construction is used in the process.

For constructing a right angle without a protractor, which of the following meth

Question

For constructing a right angle without a protractor, which of the following method/s is/are used?

Options:

A . Angle Bisector

B .

60^{\circ}

angle construction

C . Median

D . Construction of triangle

Answer: Option A
:
A and B

To construct a right angle triangle, the following steps should be followed:
1. Draw a line OB of given length.
2. With O as centre, make an arc of any radius intersecting OB at X.
3. With X as a centre, draw another arc keeping the radius same intersecting the previous arc at D.
4. $∠$ DOB will be 60 $^{\circ}$ .
5. With D as a centre and keeping the radius same, draw another arc intersecting the first arc at C.
6. $∠$ COB will be 120 $^{\circ}$ .
7. Bisect COD drawing two equal arcs from each points intersecting at E.
8. Join EO and extend till A. $∠$ AOB will be 90 $^{\circ}$ .
So, it can be seen that both 60 $^{\circ}$ and angle bisector construction is used in the process.