Question
Answer: Option D
:
D
option (d)f(x) = [(x + 1)/x] [(x + 2)/(x +1)] … [(x +n + 1)/(x + n)] = [(x + n + 1)/x]g(x) = [(x – 1)/x] [(x -2)/(x – 1)] … [(x-n-1)/(x – n)] = [(x – n -1)/x]f(x) + g(x) = (x + n + 1 + x - n – 1)/x = 2 Hence option (d)Shortcut:- Single SubstitutionPut x=1, n=0f(x)= 2g(x)=0 => f(x) +g(x) =2put x=1 and n=0 and look for 2 in the answer options. Answer is option (d)
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:
D
option (d)f(x) = [(x + 1)/x] [(x + 2)/(x +1)] … [(x +n + 1)/(x + n)] = [(x + n + 1)/x]g(x) = [(x – 1)/x] [(x -2)/(x – 1)] … [(x-n-1)/(x – n)] = [(x – n -1)/x]f(x) + g(x) = (x + n + 1 + x - n – 1)/x = 2 Hence option (d)Shortcut:- Single SubstitutionPut x=1, n=0f(x)= 2g(x)=0 => f(x) +g(x) =2put x=1 and n=0 and look for 2 in the answer options. Answer is option (d)
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