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Question


Find the zeroes of the polynomial x22.
 


Options:
A .   2 and 5
B .   4 and 3
C .   2 and 2
D .   5 and 2 
Answer: Option C
:
C

To find the zeroes, equate the given polynomial to zero.
x22=0
Using  the identity, a2b2=(a+b)(ab)
(x+2)(x2)=0 
x+2=0 and x2=0
x=2 and x=2
Hence, the zeroes are 2,2



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