Question
Find the smallest number which is divisible by the first four prime numbers. What is the highest common factor of the first four prime numbers? [3 MARKS]
Answer:
:
Smallest Number: 1 Mark
Highest Common factor: 2 Marks
The first four prime numbers are 2, 3, 5, 7.
1 is neither a prime nor a composite number so we will not include that.
Now, all these numbers are prime numbers,so the smallest number possible which is a factor of these numbers is the lowest common multiple of these numbers.
Since these are all prime numbers, their lowest common multiple is the product of these numbers, which is:
2 × 3 × 5 × 7 = 210
Hence, 210 is the required number.
The given numbers are prime numbers, so all of them will have the highest common factor equal to 1.
Was this answer helpful ?
:
Smallest Number: 1 Mark
Highest Common factor: 2 Marks
The first four prime numbers are 2, 3, 5, 7.
1 is neither a prime nor a composite number so we will not include that.
Now, all these numbers are prime numbers,so the smallest number possible which is a factor of these numbers is the lowest common multiple of these numbers.
Since these are all prime numbers, their lowest common multiple is the product of these numbers, which is:
2 × 3 × 5 × 7 = 210
Hence, 210 is the required number.
The given numbers are prime numbers, so all of them will have the highest common factor equal to 1.
Was this answer helpful ?
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