Find the remainder when 9 400 + 9 401 + 9 402 . . . . . . . 9 410 is divided by 6? Options: A . &nbsp 0 B . &nbsp 1 C . &nbsp 3 D . &nbsp 2

Answer: Option C : C Any power of 9 when divided by 6, gives a remainder 3. hence answer = 11 × 3 6 ((As there are 11 terms)= 33 6 = Remainder = 3

Find the remainder when 9400+9401+9402.......9410 is divided by 6?

Question

Find the remainder when $9^{400} + 9^{401} + 9^{402} . . . . . . . 9^{410}$ is divided by 6?

Options:

A . 0

B . 1

C . 3

D . 2

Answer: Option C
:
C

Any power of 9 when divided by 6, gives a remainder 3. hence answer $= \frac{11 \times 3}{6}$ ((As there are $11$ terms)= $\frac{33}{6}$ = Remainder $= 3$

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