Question
Find the area of a parallelogram ABCD in which AB = 3 cm and BC = 4 cm and AC = 5 cm using Heron's formula.
Answer: Option B
:
B
Since ABCD is a parallelogram, its opposite sides will be equal.
AB = 3 cm, BC =4 cm and AC = 5 cm
Now in triangle ABC,
Area of the triangle using heron’s formula,
s=Perimeter2=3+4+52=6cm
Area =√s(s−a)(s−b)(s−c)
=√6(6−3)(6−4)(6−5)
= √36
= 6cm2
Area of the parallelogram = 2 (Area of triangle ABC)
⇒The area of the parallelogram=2×6=12cm2
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:
B
Since ABCD is a parallelogram, its opposite sides will be equal.
AB = 3 cm, BC =4 cm and AC = 5 cm
Now in triangle ABC,
Area of the triangle using heron’s formula,
s=Perimeter2=3+4+52=6cm
Area =√s(s−a)(s−b)(s−c)
=√6(6−3)(6−4)(6−5)
= √36
= 6cm2
Area of the parallelogram = 2 (Area of triangle ABC)
⇒The area of the parallelogram=2×6=12cm2
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