Father is aged three times more than his son Ronit. After 8 years, he would be t

Question

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronits age. After further 8 years, how many times would he be of Ronits age?

Options:

A . 2 times

B . \(2\frac{1}{2}\)

C . \(2\frac{3}{4}\)

D . 3 times

Answer: Option A

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4xyears.

Therefore (4x + 8) = \(\frac{5}{2}\left(x+8\right)\)

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = \(\frac{(4x+16)}{(x+16)}\) = \(\frac{48}{24}\) = 2.

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