Question
Construct a triangle ABC, where ∠BAC=∠ACB. Let D be any point on the line AB, such that the ∠CBD=120∘, AB = 3 m. [2 MARKS]
Answer: Option A
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Steps: 1 Mark
Construction: 1 Mark
Draw a line segment AB = 3 m and extend it.
Sum of two interior opposite angles is equal to the exterior angle.
∠BAC+∠ACB=120∘
Hence, ∠ABC=60∘
Hence, the given triangle is an equilateral triangle.
Draw AB = 3 m
Draw a line AC of length 3 m making an angle of 60 degrees with AB. Join BC.
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