Question
C and D are the children of A & B, who are married to each other. D is 5 years younger than C. Five years ago, A was twice as old as C. The current age of B is the average of A and C’s ages. If the average age of all of them is 34 years, find the current age of D?
Answer: Option C
:
C
Let the present age of each of them be the letters themselves.
Present age of D= C-5
Presnt age of A will be 2(C-5)+5
=2C-5 and the present age of B will be C+2C−52=(3C−5)2
Average age of members =34
C+C−5+2C−5+(3C−5)2=34×4
4C+(3C−5)2=146
11C= 297
C=27
D= 27-5=22
Option (C)
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:
C
Let the present age of each of them be the letters themselves.
Present age of D= C-5
Presnt age of A will be 2(C-5)+5
=2C-5 and the present age of B will be C+2C−52=(3C−5)2
Average age of members =34
C+C−5+2C−5+(3C−5)2=34×4
4C+(3C−5)2=146
11C= 297
C=27
D= 27-5=22
Option (C)
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