Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________ Options: A . &nbsp\(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \) B . &nbsp\(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\) C . &nbsp\(F_e \sqrt{P_e}=(F_1*F_2) \sqrt{P}\) D . &nbsp\(F_e \sqrt{P_e}=(F_1/F_2) \sqrt{P}\)

Based on the equal deflection criterion, the expression for the equivalent wheel

Question

Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________

Options:

A . \(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \)

B . \(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\)

C . \(F_e \sqrt{P_e}=(F_1*F_2) \sqrt{P}\)

D . \(F_e \sqrt{P_e}=(F_1/F_2) \sqrt{P}\)

Answer: Option A
Answer: (a).\(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \)

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