Question
As a corporate policy, MnD Ltd. had decided that no bug would be found in more than two solutions and, so, those found in three solutions should be withdrawn from exactly one solution. The number of bugs withdrawn from the Elevate solution is two less than the number of bugs withdrawn from the Financo solution which, in turn, is two less than the number of bugs withdrawn from the Edusoft solution. Now, which of the following statements is/are definitely true?
Answer: Option C
:
C
Let the number of bugs in Edusoft, Elevate and Financo solution alone be a, b and c respectively. Number of bugs in all the solution = x and number of bugs in Edusoft and Elevate solutions alone be d, Elevate and Financo solutions alone be g and Number of bugs in Edusoft and Financo solutions alone e.
Acc to passage,
C = 2x............eq(i)
a=3x -4...........eq(ii)
b=4+x....................eq(iii)
It is given that Total number of bugs in Edusoft solution is 24,
Hence,
3x -4+x+d+e = 24.......eq(iv)
4x +d+e=28
d:e:f=1:2:3 (in some order)
From last time of the passage
⇒ 3x - 4 =14
⇒ x =6This implies d + e = 4, d =1 or 3or e = 1 or 3
Total number of bugs = 14+12+10+6+2+(d+e)
= 48
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:
C
Let the number of bugs in Edusoft, Elevate and Financo solution alone be a, b and c respectively. Number of bugs in all the solution = x and number of bugs in Edusoft and Elevate solutions alone be d, Elevate and Financo solutions alone be g and Number of bugs in Edusoft and Financo solutions alone e.
Acc to passage,
C = 2x............eq(i)
a=3x -4...........eq(ii)
b=4+x....................eq(iii)
It is given that Total number of bugs in Edusoft solution is 24,
Hence,
3x -4+x+d+e = 24.......eq(iv)
4x +d+e=28
d:e:f=1:2:3 (in some order)
From last time of the passage
⇒ 3x - 4 =14
⇒ x =6This implies d + e = 4, d =1 or 3or e = 1 or 3
Total number of bugs = 14+12+10+6+2+(d+e)
= 48
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