Question
Answer these questions based on the following data.
In a standard 5 class, the students are arranged according to the increasing order of their marks in an examination. The marks obtained by every student, starting from the third student, are the sum of the marks obtained by the earlier two students.
Marks scored by students are in A.P. If the 12th student got 809 marks and the 2nd student got 6 marks, then what is the sum of the marks obtained by the first ten students?
In a standard 5 class, the students are arranged according to the increasing order of their marks in an examination. The marks obtained by every student, starting from the third student, are the sum of the marks obtained by the earlier two students.
Marks scored by students are in A.P. If the 12th student got 809 marks and the 2nd student got 6 marks, then what is the sum of the marks obtained by the first ten students?
Answer: Option B
:
B
By observation, we get
T12=S(n−2)+t2
It is given that
T12 = 809 and t2=6
T12=S(12−2)+t2
⇒t12=S10+t2
⇒S10=809−6=803
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:
B
By observation, we get
T12=S(n−2)+t2
It is given that
T12 = 809 and t2=6
T12=S(12−2)+t2
⇒t12=S10+t2
⇒S10=809−6=803
Was this answer helpful ?
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