Question
An iron spherical ball of radius 21cm is melted and it is re-casted in hemispheres of radius 7cm. The number of balls formed will be
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Answer:
:
The volume will remain constant.
Let's assume x such hemispherical balls will be formed.
So 43πR3=x23πr3
(Where R is the radius of spherical ball and r is the radius of thehemispheres)
⇒43π(21)3=x23π(7)3
⇒x=2×21×21×217×7×7
⇒x=54
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:
The volume will remain constant.
Let's assume x such hemispherical balls will be formed.
So 43πR3=x23πr3
(Where R is the radius of spherical ball and r is the radius of thehemispheres)
⇒43π(21)3=x23π(7)3
⇒x=2×21×21×217×7×7
⇒x=54
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