An earth satellite of mass m revolves in a circular orbit at a height h from the

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An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

Options:

A . gR2R+h

B . gR

C . gRR+h

D . √gR2R+h

Answer: Option D
:
D

v_{0} = \sqrt{\frac{G M}{r}} = \sqrt{\frac{g R^{2}}{R + h}}

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