An alloy contains copper and tin in the ratio 3 : 2. If 250 gm of copper is adde

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An alloy contains copper and tin in the ratio 3 : 2. If 250 gm of copper is added to this alloy then the copper in it becomes double the quantity of tin in it. What is the amount (in gm) of tin in the alloy?

Options:

A . 500

B . 1000

C . 750

D . 250

Answer: Option A

Amount of pure milk= a(1 ?b/a)n(n = 3, a = pure milk and b = amount replaced)= 960 (1 ?48/960)^3= 960(1-1/20)^3= 960 * 19/20 * 19/20*19/20= 823.08 lt.

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