according to parallel axis theorem, the moment of inertia of a section about an

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According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. ip) is given by(where, a = area of the section, ig = moment of inertia of the section about an axis passing through its c.g., and h = distance between c.g. and the parallel axis.)

Options:

A . IP = IG + Ah2

B . IP = IG - Ah2

C . IP = IG / Ah2

D . IP = Ah2 / IG

Answer: Option A

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