Question
ABCD is a parallelogram and P,Q are the midpoints of DC and AB respectively. Then, area of parallelogram AQPD is equal to area of triangle ADB.
Answer: Option A
:
A
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A
Parallelogram ABCD and triangle ABD are on the same base and between same parallels .
Area(△ADB) = 12 Area of parallelogram(ABCD)
As P and Q are the midpoints of DC and AB, Area of parallelogram(AQPD) = 12Area of parallelogram(ABCD)
So, Area(△ADB) = Area of parallelogram(AQPD)
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