Question
A transmitter supplies 9 kW to the aerial when unmodulated. The power radiated when modulated to 40% is
Answer: Option B
:
B
Pt = Pc[1+m22] = 9 [1 + (0.4)22]
= 9 [1 + 0.162] (∵ m = 40 % = 0.4)
= 9 (1.08) = 9.72 kW
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:
B
Pt = Pc[1+m22] = 9 [1 + (0.4)22]
= 9 [1 + 0.162] (∵ m = 40 % = 0.4)
= 9 (1.08) = 9.72 kW
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