Question
A circle of radius 3 crosses the centre of a square of side length 2. Find the approximate positive difference between the areas of the non-overlapping portions of the figures
Answer: Option B
:
B
Let the area of the square = s, the area of the circle = c, and the area of the overlapping portion = x. The area of the circle not overlapped by the square is "c - x” and the area of the square not overlapped by the circle is "s - x”, so the difference between these two is (c - x) - (s - x) = c - s = 9π2- 4 .(approximately = 24.26). Hence the correct answer is option (b).
Was this answer helpful ?
:
B
Let the area of the square = s, the area of the circle = c, and the area of the overlapping portion = x. The area of the circle not overlapped by the square is "c - x” and the area of the square not overlapped by the circle is "s - x”, so the difference between these two is (c - x) - (s - x) = c - s = 9π2- 4 .(approximately = 24.26). Hence the correct answer is option (b).
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution